Quantitative Aptitude

Permutation and Combination; Probability

C-CAT

Permutation and Combination

19.1 Fundamental Counting Principle

If task 1 can be done in m ways and task 2 in n ways:

  • If BOTH needed (AND): m × n ways (Multiplication)
  • If EITHER needed (OR): m + n ways (Addition)

19.2 Factorial

n! = n × (n-1) × (n-2) × ... × 2 × 1

Special cases: 0! = 1, 1! = 1

19.3 Permutation (Order Matters)

ⁿPᵣ = n! / (n-r)!

Reads: "n choose r with order"

Example: ⁵P₃ = 5!/(5-3)! = 5!/2! = 60

When items are repeated:

  • Permutations of n items where a items are same, b items are same:

    = n! / (a! × b!)

Example: MATHEMATICS (11 letters, M×2, A×2, T×2):

  • = 11! / (2! × 2! × 2!) = 4,989,600

19.4 Combination (Order Doesn't Matter)

ⁿCᵣ = n! / [r! × (n-r)!]

Key Properties:

  • ⁿCᵣ = ⁿC(n-r)
  • ⁿC₀ = ⁿCₙ = 1
  • ⁿC₁ = n
  • ⁿCᵣ + ⁿCᵣ₋₁ = ⁿ⁺¹Cᵣ (Pascal's Identity)

19.5 Permutation vs Combination

SituationUse
Arrangement (order matters)Permutation
Selection (order doesn't matter)Combination
Passwords, rankings, wordsPermutation
Committees, teams, groupsCombination
Sitting arrangements (line)Permutation
Sitting arrangements (circle)(n-1)!

19.6 Special Cases

Circular Arrangement

  • n objects in a circle = (n-1)! ways
  • n objects on a necklace (both sides identical) = (n-1)! / 2

Choosing with Restrictions

At least / at most problems: Use complementary counting

  • At least 1 = Total - (choosing
  • At most 2 = Choose 0 + Choose 1 + Choose 2

Example: From 6 men 4 women, committee of 5 with at least 2 women:

  • = (4C2)(6C3) + (4C3)(6C2) + (4C4)(6C1) + (4C5)(6C0) Wait: at least 2 women:
  • 2W + 3M = 4C2 × 6C3 = 6 × 20 = 120
  • 3W + 2M = 4C3 × 6C2 = 4 × 15 = 60
  • 4W + 1M = 4C4 × 6C1 = 1 × 6 = 6
  • Total = 186

Words from a Word (vowels together)

  • Treat vowels as a single unit
  • Arrange (consonants + 1 unit) + arrange vowels within unit

Example: OPTICAL (7 letters, vowels O, I, A):

  • Vowels together: treat OIA as 1 block → 5! arrangements
  • Vowels within block: 3! = 6
  • Total = 5! × 3! = 120 × 6 = 720

19.7 nPr and nCr Quick Lookups

nrnPrnCr
522010
536010
623015
6312020
1029045
103720120
50224501225

Probability

20.1 Basic Definition

Probability = Favorable Outcomes / Total Outcomes

  • P(E) ranges from 0 to 1
  • P(sure event) = 1
  • P(impossible event) = 0
  • P(E) + P(E') = 1 → P(E') = 1 - P(E) (Complementary events)

20.2 Sample Spaces

Coin Toss

  • 1 coin: S = {H, T}, n(S) = 2
  • 2 coins: S = {HH, HT, TH, TT}, n(S) = 4
  • 3 coins: n(S) = 8
  • n coins: n(S) = 2ⁿ

Dice Roll

  • 1 die: S = {1,2,3,4,5,6}, n(S) = 6
  • 2 dice: n(S) = 36

Card Deck (52 cards)

  • 4 suits: Spades ♠, Hearts ♥, Diamonds ♦, Clubs ♣
  • Each suit: 13 cards (A, 2-10, J, Q, K)
  • Red cards: Hearts + Diamonds = 26
  • Black cards: Spades + Clubs = 26
  • Face cards: J, Q, K in each suit = 12 total
  • Aces: 4 total

20.3 Key Probability Formulas

EventFormula
P(A or B) — UnionP(A) + P(B) - P(A∩B)
P(A and B) — IntersectionP(A) × P(B) [if independent]
P(AB) — Conditional
Mutually exclusive eventsP(A∩B) = 0, P(A∪B) = P(A) + P(B)
Independent eventsP(A∩B) = P(A) × P(B)

20.4 Common Probability Examples

Drawing from a bag of balls:

  • P(red) = (number of red balls) / (total balls)

Drawing cards:

  • P(face card) = 12/52 = 3/13
  • P(king of red) = 2/52 = 1/26
  • P(queen or king) = 8/52 = 2/13

Rolling dice:

  • P(sum = 7 with 2 dice) = 6/36 = 1/6 (pairs: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1)
  • P(at least one six) = 1 - P(no six) = 1 - (5/6)² = 11/36

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