Quantitative Aptitude
Pipes and Cisterns; Time, Speed and Distance; Problems on Trains
C-CAT
Pipes and Cisterns
13.1 Concept
Pipes and Cisterns problems are exactly like Time and Work:
- Inlet pipe (filling) = Positive work
- Outlet pipe (emptying) = Negative work
If a pipe fills a tank in n hours → it fills 1/n of the tank in 1 hour.
13.2 Key Formulas
| Scenario | Formula |
|---|---|
| Pipe A fills in 'a' hrs, Pipe B in 'b' hrs | Together: ab/(a+b) hours |
| A fills in 'a', B empties in 'b' (a < b) | Net filling time: ab/(b-a) |
| A fills in 'a', B empties in 'b' (a > b) | Net emptying time: ab/(a-b) |
13.3 LCM Method for Pipes
Example: Pipe A fills in 6 hr, B fills in 8 hr, C empties in 12 hr. Time to fill:
LCM(6, 8, 12) = 24 (capacity of tank)
- A's rate = 24/6 = 4 units/hr (fills)
- B's rate = 24/8 = 3 units/hr (fills)
- C's rate = 24/12 = 2 units/hr (empties)
- Net rate = 4 + 3 - 2 = 5 units/hr
- Time = 24/5 = 4.8 hours
13.4 Alternate Opening of Pipes
If pipes work alternately for fixed periods, calculate work done in each cycle.
Example: A fills in 10 hr, B empties in 15 hr. They open alternately every hour (A first):
- In 1st hour (A): +1/10
- In 2nd hour (B): -1/15
- Net in 2 hours = 1/10 - 1/15 = 3/30 - 2/30 = 1/30
- Time for full tank = 2 × 30 = 60 hours
Time, Speed and Distance
14.1 Core Formula
Distance = Speed × Time
Speed = Distance / Time
Time = Distance / Speed
14.2 Unit Conversions
| From | To | Multiply by |
|---|---|---|
| km/hr | m/s | × 5/18 |
| m/s | km/hr | × 18/5 |
Memory Trick:
- km/hr → m/s: divide by 3.6 (or × 5/18)
- m/s → km/hr: multiply by 3.6 (or × 18/5)
Example: 72 km/hr = 72 × 5/18 = 20 m/s
14.3 Average Speed
When equal DISTANCES are covered at different speeds:
Average Speed = 2S₁S₂ / (S₁ + S₂) (Harmonic Mean)
When equal TIMES are spent at different speeds:
Average Speed = (S₁ + S₂) / 2 (Arithmetic Mean)
Important: Do NOT use arithmetic mean when distances are equal!
14.4 Relative Speed
| Direction | Relative Speed |
|---|---|
| Same direction | |
| Opposite direction | S₁ + S₂ |
14.5 Meeting Problems
Two persons start simultaneously from A and B moving towards each other:
- They meet after time = Total Distance / (Sum of speeds)
Two persons start simultaneously from A and B moving away:
- Distance between them after t hours = (S₁ + S₂) × t
14.6 Problems on Chasing
If A is ahead of B by distance 'd' and both move in same direction:
- B is faster (B catches A): Time = d / (S_B - S_A)
- A runs away from B: They keep diverging if A is faster
Problems on Trains
15.1 Key Rules
- Length of train is crucial — it must cross the obstacle completely
- Distance = Length of train (when crossing a pole/person/tree)
- Distance = Length of train + Length of object (when crossing bridge/platform/another train)
15.2 Formulas
| Situation | Formula |
|---|---|
| Train crosses a pole/man | L₁ = Speed × Time |
| Train crosses a platform | L₁ + L₂ = Speed × Time |
| Train passes moving man (same dir) | L₁ = (S₁ - S₂) × t |
| Train passes moving man (opp dir) | L₁ = (S₁ + S₂) × t |
| Two trains, same direction | L₁ + L₂ = (S₁ - S₂) × t |
| Two trains, opposite direction | L₁ + L₂ = (S₁ + S₂) × t |
15.4 Common Pattern
Example: Train 200m long passes a platform 150m long in 14 seconds. Find speed:
- Total distance = 200 + 150 = 350 m
- Speed = 350 / 14 = 25 m/s = 90 km/hr
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