Quantitative Aptitude
Ratio and Proportion; Mixture and Alligation
C-CAT
Ratio and Proportion
6.1 Definitions
Ratio a:b = a/b
- a = antecedent, b = consequent
- Ratio has NO units
- Can be simplified like fractions
Proportion: If a:b = c:d, then a, b, c, d are in proportion
- Written as a:b::c:d
Product of means = Product of extremes
- b × c = a × d (cross multiplication)
6.2 Types of Proportions
| Type | Definition |
|---|---|
| Fourth Proportional | If a:b = c:x, then x = bc/a |
| Third Proportional | If a:b = b:x, then x = b²/a |
| Mean Proportional | If a:x = x:b, then x = √(ab) |
6.3 Compounded Ratio
- If a:b and c:d are two ratios, their compound ratio = ac:bd
6.4 Duplicate/Triplicate/Sub-duplicate Ratios
| Ratio Type | Expression |
|---|---|
| Duplicate of a:b | a²:b² |
| Triplicate of a:b | a³:b³ |
| Sub-duplicate of a:b | √a:√b |
| Sub-triplicate of a:b | ∛a:∛b |
6.5 Working With Multiple Ratios
To find A:B:C when A:B and B:C are given:
- Make B's value common
- A:B = 3:4, B:C = 5:6
- Multiply: A:B:C = (3×5):(4×5):(4×6) = 15:20:24
Example Problem: If A:B = 3:4, B:C = 5:6, C:D = 7:8:
- A:B = 3:4 → multiply both by 5 → 15:20
- B:C = 5:6 → multiply both by 4 → 20:24
- C:D = 7:8 → multiply both by 3 → 21:24... adjust to 24:..
- (C in B:C = 24) and (C in C:D should match)
- A:B:C = 15:20:24 and D = 24 × 8/7 → adjust
- Final: A:B:C:D = 2×4×6 : 3×4×6 : 3×5×6 : 3×5×7
6.6 Proportion in Direct and Inverse
Direct Proportion: If A increases, B increases proportionally
- A ∝ B → A = kB → A₁/A₂ = B₁/B₂
Inverse Proportion: If A increases, B decreases
- A ∝ 1/B → A₁/A₂ = B₂/B₁
6.7 Dividing a Number in a Given Ratio
- To divide N in ratio a:b:c → parts are Na/(a+b+c), Nb/(a+b+c), Nc/(a+b+c)
Mixture and Alligation
7.1 Alligation Rule (Cross Method)
Used when two ingredients at different prices are mixed to give a mixture at a mean price.
Cheaper (C) Dearer (D)
\ /
\ /
Mean Price (M)
/ \
/ \
(D - M) (M - C)
Ratio of mixing = (D - M) : (M - C)
7.2 Rule of Alligation Formula
(Quantity of Cheaper) / (Quantity of Dearer) = (D - M) / (M - C)
7.3 Understanding Alligation
- Cheaper Component Amount = D - M (dearer price minus mean price)
- Dearer Component Amount = M - C (mean price minus cheaper price)
Example: A mixture of Rs. 8/kg and Rs. 12/kg tea sells at Rs. 10/kg. Find ratio of mixing.
- Cheaper = 8, Dearer = 12, Mean = 10
- Ratio = (12-10) : (10-8) = 2:2 = 1:1
7.4 Repeated Dilution Formula
When from a vessel containing V litres of pure liquid, x litres are taken out and replaced by water, after n operations:
Quantity of pure liquid = V × (1 - x/V)ⁿ
Example: A cask contains 40 litres of milk. 4 litres removed and 4 litres water added 3 times. Milk remaining:
- = 40 × (1 - 4/40)³ = 40 × (9/10)³ = 40 × 729/1000 = 29.16 litres
7.5 Water and Milk Mixture Problems
If mixture has milk:water = a:b and we add x litres of water:
- New ratio of water = (Original water amount + x) : original milk amount
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