Quantitative Aptitude
Divisibility Rules; LCM and HCF
C-CAT
Divisibility Rules
2.1 Rules for Each Number
| Divisor | Rule |
|---|---|
| 2 | Last digit is even (0, 2, 4, 6, 8) |
| 3 | Sum of all digits is divisible by 3 |
| 4 | Last 2 digits form a number divisible by 4 (or last 2 digits are 00) |
| 5 | Last digit is 0 or 5 |
| 6 | Divisible by both 2 AND 3 |
| 7 | Double the last digit, subtract from rest; result divisible by 7 |
| 8 | Last 3 digits form a number divisible by 8 (or last 3 digits are 000) |
| 9 | Sum of all digits is divisible by 9 |
| 10 | Last digit is 0 |
| 11 | (Sum of digits at odd positions) − (Sum of digits at even positions) = 0 or multiple of 11 |
| 12 | Divisible by both 3 AND 4 |
| 25 | Last 2 digits are 00, 25, 50 or 75 |
2.2 Examples
Check divisibility of 792 by 11:
- Odd position digits (from right): 7, 9, 2 → No wait
Actually: positions from LEFT: 7(pos 1), 9(pos 2), 2(pos 3)
- Odd position sum = 7 + 2 = 9
Even position sum = 9
- Difference = 9 - 9 = 0 → Divisible by 11 ✓
Check if 348 is divisible by 4:
- Last 2 digits = 48
- 48 ÷ 4 = 12 → Yes ✓
Check if 4563 is divisible by 3:
- Sum of digits = 4 + 5 + 6 + 3 = 18
- 18 ÷ 3 = 6 → Yes ✓
2.3 Divisibility Rule for 7 (Detailed)
- Take the number, double the last digit, subtract from the remaining number
- Repeat until you get a small number
- Example: 343 → 34 - (2×3) = 34 - 6 = 28 → 28 is divisible by 7 → 343 is divisible by 7 ✓
LCM and HCF
3.1 Key Definitions
HCF (Highest Common Factor) = GCD = Greatest Common Divisor
- The LARGEST number that divides all given numbers exactly
- Also called GCD (Greatest Common Divisor)
LCM (Least Common Multiple)
- The SMALLEST number that is exactly divisible by all given numbers
3.2 Key Relationship
HCF × LCM = Product of two numbers (valid for exactly 2 numbers only)
If HCF of two numbers is H and LCM is L and one number is a, then other = (H × L) / a
3.3 Methods to Find HCF
Prime Factorization Method
- Factorize each number into prime factors
- HCF = Product of LOWEST powers of common factors
Example: HCF(12, 18, 24)
- 12 = 2² × 3
- 18 = 2 × 3²
- 24 = 2³ × 3
- HCF = 2¹ × 3¹ = 6
Division Method (Euclid's Algorithm)
- Divide larger by smaller, remainder becomes divisor, previous divisor becomes dividend
- Continue until remainder = 0
- Last divisor = HCF
Example: HCF(48, 18)
- 48 ÷ 18 = 2 remainder 12
- 18 ÷ 12 = 1 remainder 6
- 12 ÷ 6 = 2 remainder 0
- HCF = 6
3.4 Methods to Find LCM
Prime Factorization Method
- LCM = Product of HIGHEST powers of all prime factors
Example: LCM(12, 18, 24)
- 12 = 2² × 3
- 18 = 2 × 3²
- 24 = 2³ × 3
- LCM = 2³ × 3² = 8 × 9 = 72
Division Method
- Write all numbers in a row
- Divide by smallest prime that divides at least one number
- Continue until all quotients are 1
- LCM = Product of all divisors used
3.5 Important Formulas
| Situation | Formula |
|---|---|
| HCF of fractions | HCF(numerators) / LCM(denominators) |
| LCM of fractions | LCM(numerators) / HCF(denominators) |
3.6 Word Problems — Key Tricks
When remainder is same and given:
If N leaves remainder r with a, b, c → N - r is divisible by HCF(a, b, c)
- Find HCF of (a, b, c) and add r
Example: Find the greatest number that divides 276, 690 and 1610 leaving remainder 6:
Subtract remainder: 270, 684, 1604
- HCF(270, 684, 1604) = HCF using difference method
- 690
- 276 = 414; 1610 - 690 = 920
- HCF(414, 920) = 46 → Greatest number = 46
When remainders are different:
- If N leaves different remainders r1, r2, r3 with a, b, c respectively:
- (a - r1) = (b - r2) = (c - r3) = constant k
- N = LCM(a, b, c) - k
LCM with common remainder:
- Result = LCM(a, b, c) + common remainder
HCF(42, 63, 105):
- 42 = 2 × 3 × 7
- 63 = 3² × 7
- 105 = 3 × 5 × 7
- HCF = 3 × 7 = 21
If HCF = 8, LCM should have factor of 8
- If four numbers are in ratio a:b:c:d with HCF = h → numbers = ah, bh, ch, dh
- Example: Four numbers in ratio 10:12:15:18 with HCF = 3 → Numbers = 30, 36, 45, 54
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