Quantitative Aptitude

Divisibility Rules; LCM and HCF

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Divisibility Rules

2.1 Rules for Each Number

DivisorRule
2Last digit is even (0, 2, 4, 6, 8)
3Sum of all digits is divisible by 3
4Last 2 digits form a number divisible by 4 (or last 2 digits are 00)
5Last digit is 0 or 5
6Divisible by both 2 AND 3
7Double the last digit, subtract from rest; result divisible by 7
8Last 3 digits form a number divisible by 8 (or last 3 digits are 000)
9Sum of all digits is divisible by 9
10Last digit is 0
11(Sum of digits at odd positions) − (Sum of digits at even positions) = 0 or multiple of 11
12Divisible by both 3 AND 4
25Last 2 digits are 00, 25, 50 or 75

2.2 Examples

Check divisibility of 792 by 11:

  • Odd position digits (from right): 7, 9, 2 → No wait

Actually: positions from LEFT: 7(pos 1), 9(pos 2), 2(pos 3)

  • Odd position sum = 7 + 2 = 9

Even position sum = 9

  • Difference = 9 - 9 = 0 → Divisible by 11 ✓

Check if 348 is divisible by 4:

  • Last 2 digits = 48
  • 48 ÷ 4 = 12 → Yes ✓

Check if 4563 is divisible by 3:

  • Sum of digits = 4 + 5 + 6 + 3 = 18
  • 18 ÷ 3 = 6 → Yes ✓

2.3 Divisibility Rule for 7 (Detailed)

  • Take the number, double the last digit, subtract from the remaining number
  • Repeat until you get a small number
  • Example: 343 → 34 - (2×3) = 34 - 6 = 28 → 28 is divisible by 7 → 343 is divisible by 7 ✓

LCM and HCF

3.1 Key Definitions

HCF (Highest Common Factor) = GCD = Greatest Common Divisor

  • The LARGEST number that divides all given numbers exactly
  • Also called GCD (Greatest Common Divisor)

LCM (Least Common Multiple)

  • The SMALLEST number that is exactly divisible by all given numbers

3.2 Key Relationship

HCF × LCM = Product of two numbers (valid for exactly 2 numbers only)

If HCF of two numbers is H and LCM is L and one number is a, then other = (H × L) / a

3.3 Methods to Find HCF

Prime Factorization Method

  • Factorize each number into prime factors
  • HCF = Product of LOWEST powers of common factors

Example: HCF(12, 18, 24)

  • 12 = 2² × 3
  • 18 = 2 × 3²
  • 24 = 2³ × 3
  • HCF = 2¹ × 3¹ = 6

Division Method (Euclid's Algorithm)

  • Divide larger by smaller, remainder becomes divisor, previous divisor becomes dividend
  • Continue until remainder = 0
  • Last divisor = HCF

Example: HCF(48, 18)

  • 48 ÷ 18 = 2 remainder 12
  • 18 ÷ 12 = 1 remainder 6
  • 12 ÷ 6 = 2 remainder 0
  • HCF = 6

3.4 Methods to Find LCM

Prime Factorization Method

  • LCM = Product of HIGHEST powers of all prime factors

Example: LCM(12, 18, 24)

  • 12 = 2² × 3
  • 18 = 2 × 3²
  • 24 = 2³ × 3
  • LCM = 2³ × 3² = 8 × 9 = 72

Division Method

  • Write all numbers in a row
  • Divide by smallest prime that divides at least one number
  • Continue until all quotients are 1
  • LCM = Product of all divisors used

3.5 Important Formulas

SituationFormula
HCF of fractionsHCF(numerators) / LCM(denominators)
LCM of fractionsLCM(numerators) / HCF(denominators)

3.6 Word Problems — Key Tricks

When remainder is same and given:

If N leaves remainder r with a, b, c → N - r is divisible by HCF(a, b, c)

  • Find HCF of (a, b, c) and add r

Example: Find the greatest number that divides 276, 690 and 1610 leaving remainder 6:

Subtract remainder: 270, 684, 1604

  • HCF(270, 684, 1604) = HCF using difference method
  • 690
  • 276 = 414; 1610 - 690 = 920
  • HCF(414, 920) = 46 → Greatest number = 46

When remainders are different:

  • If N leaves different remainders r1, r2, r3 with a, b, c respectively:
    • (a - r1) = (b - r2) = (c - r3) = constant k
    • N = LCM(a, b, c) - k

LCM with common remainder:

  • Result = LCM(a, b, c) + common remainder

HCF(42, 63, 105):

  • 42 = 2 × 3 × 7
  • 63 = 3² × 7
  • 105 = 3 × 5 × 7
  • HCF = 3 × 7 = 21

If HCF = 8, LCM should have factor of 8

  • If four numbers are in ratio a:b:c:d with HCF = h → numbers = ah, bh, ch, dh
  • Example: Four numbers in ratio 10:12:15:18 with HCF = 3 → Numbers = 30, 36, 45, 54

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